Problems on Chapter 4
V25.0109 General Chemistry I
Honors
TA: Vaishnav Krishnan
NAME: ______________________
1.
Last
week you balanced the following reactions.
Now, assign oxidation states
to every atom in the reaction.
Ca3(PO4)2 +
SiO2 + C
ŕ CaSiO3
+ P4 +
CO
Cu(NH3)4Cl2 +
NH3 + Cu
ŕ Cu(NH3)4Cl
Would the oxidation state
depend on whether you balanced the chemical reaction correctly? Does an atom’s oxidation state depend on the
physical state of its molecule? If atoms and molecules are so stupid, then for
those atoms in the so-called ‘Transition block’, what determines the oxidation
state that they possess in a given compound?
2.
Balance
the following reactions using a method that involves half reactions. The medium
in which the reaction proceeds has been provided in parentheses. Identify the
reducing and oxidizing agents in the reactions.
a.
Cr2O72-
+ CH3OH ŕ HCO2H + Cr3+ (acidic)
b.
As
+ ClO3-1 ŕ H3AsO3
+ HClO (basic)
3.
A
6.977g sample of a mixture was analyzed for barium ion by adding a small excess
of sulfuric acid to an aqueous solution of the sample. The resultant reaction
produced a precipitate of barium sulfate, which was collected by filtration,
washed dried and weighed. If 0.4123g of BaSO4 was obtained, what was
the mass percentage of barium in the sample?
(Question within a question:
How could you positively identify the precipitate as actually being barium
sulfate?)
4.
Concentrated
phosphoric acid as sold for use in the laboratory is usually 90% H3PO4
by mass (the rest is water). Such a solution contains 12.2 mol of H3PO4
per liter of solution at 25C.
a.
Compute
the density of the solution
b.
What
volume of this solution should be used to in mixing 2.00L of a 1.00M phosphoric
acid solution?
c.
What
volume of the original solution (laboratory stock solution) would be needed to
titrate 25ml of a 0.7654M solution of barium hydroxide?
5.
Goes on and on and on and on. . . Suppose 150ml of a 10% by mass solution of
sodium chloride is acidified with sulfuric acid and then treated with an excess
of MnO2(s). Under these conditions, all of the chlorine is liberated
as diatomic chlorine gas. The chlorine is collected without loss and reacts
with excess H2 to form HCl(g). The HCl is dissolved in enough water
to make 250ml of solution. 50ml of this solution is used to titrate a 1.02M
solution of NaOH. What volume of the NaOH solution would be required for this
titration?
6.
Cerium
(IV) ions are strong oxidizing agents in acidic solution, oxidizing
arsenious acid to arsenic acid according to the equation.
Ce4+ + H3AsO3
+ H2O ŕ Ce3+ + H3AsO4 + H+
A sample of As2O3
weighing 0.217g is dissolved in basic solution and then acidified to make H3AsO3.
Its titration with a solution of acidic cerium (IV) sulfate requires 21.47ml. Determine the
original concentration of Ce4+ in the titrating solution. Remember to balance this
reaction.
7.
Explain
the following in terms of energy changes.
a.
The
exothermic dissolution of a salt in water
b.
The
endothermic dissolution of a salt in water
c.
The
reason for the high insolubility of a particularly insoluble salt like barium
sulfate
8.
The Honors Super Challenge (sorry, all of my other problems on solution
stoichiometry were pretty pathetic, so here is a better one on molecular
geometry)
The molecule NH3
(ammonia) has been known to have a tetrahedral structure, with the electron
pair pointing towards one vertex of the tetrahedron, and the N-H bonds pointing
towards the other three. It is of course a ‘distorted tetrahedron’ with the HNH
angle found to be not 109.5degrees but instead 107degrees. If we scale
the approximate the length of the N-H bonds to be 1 unit long, and we position
the N atom in NH3 to sit exactly at the origin of a three
dimensional coordinate system, then calculate the three dimensional coordinates
for each of the hydrogen atoms in the molecule, if one of the N-H bonds is
aligned along the x-axis.
(Just so you know, you can
conquer half of organic chemistry if you can easily visualize the three
dimensional structure of an organic molecule. You need to be premed to conquer
the other half.)